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ordinary differential equations - How is $\frac{dx }{z(x+y) } = \frac{dy}{z(x-y) } = \frac{dz }{x^2 + y^2 } $ equivalent to $\frac{ y dx + xdy - zdz}{0}=\frac{ xdx - ydy -zdz}{0}$? -
SOLVED: EXAMPLE 4 Find dz/dx and dz/dy if z is defined implicitly as a function of x and y by the equation x6 + y6 + 26 + 12xyz 1. SOLUTION To
SOLVED: Rewrite the iterated integral 1-x 2-2y J' J' Jo f(c,y,2) dz dy dx changing the order of integration to first with respect to X, then Y, and then z. y-1 'K "
